Respuesta :

[tex]\begin{gathered} \text{The first term is 3, the common ratio is 4} \\ \text{That means;} \\ a=3,r=4 \\ \text{The nth term is } \\ T_n=ar^{(n-1)} \\ 8th=3\times4^{(8-1)} \\ 8th=3\times4^7 \\ 8th=3\times16384 \\ 8th=49152 \end{gathered}[/tex]

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