Answer:
The bridge is about 193.52 ft above the river and the length of the bridge above the arch is about 1250.51 ft
Step-by-step explanation:
The arch is represented by the equation
y = - .000495 x² + .619 x where x and y are in ft .
We can write this equation in the form
y = - a x² + bx
The vertex is on the line
x = b / 2a
= .619 / 2 x .000495
= 625.25
Putting the value in the equation above
y = - .000495 ( 625.25)²
= 193.51 ft
This value will give us the depth of river .
To know the width of bridge we shall have to solve the quadratic equation
- .000495 x² + .619 x = 0
x = [- .619 ± √ ( .619)² - 0] / 2 x .000495
= - .619 + 625.25 and
x = - .619 - 625.25
Difference = 625.25 x 2 = 1250 .51 ft.
So the width of the bridge will be 1250 .51 ft .