The slope (m) of the line that passes through the points (x1, y1) and (x2, y2) is computed as follows:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]In this case, the line passes through the points (-3, 5) and (-1, -3), then its slope is:
[tex]m=\frac{-3-5}{-1-(-3)}=\frac{-8}{2}=-4[/tex]Equation of a line in slope-intercept form
y = mx + b
where m is the slope and b is the y-intercept.
Substituting with m = -4 and the point (-3, 5), that is, x = -3 and y = 5, and solving for b:
[tex]\begin{gathered} 5=(-4)\cdot(-3)+b \\ 5=12+b \\ 5-12=12+b-12 \\ -7=b \end{gathered}[/tex]Substituting m = -4 and b = -7 into the equation, we get:
y = -4x + (- 7)
y = -4x - 7