The value of a is 6 and the value of b is 7
How to determine the values of a and b?
The function is given as:
h(x) = a . sin(x - π/2) + b
From the table of values, we have:
x = π/2 when y = 7
So, we have:
a . sin(π/2 - π/2) + b = 7
Evaluate the difference
a . sin(0) + b = 7
Evaluate the value of sin(0)
a . 0 + b = 7
Evaluate the product of a and 0
b = 7
Substitute b = 7 in h(x) = a . sin(x - π/2) + b
h(x) = a . sin(x - π/2) + 7
From the table of values, we have:
x = π when y = 13
So, we have:
a . sin(π - π/2) + 7 = 13
Evaluate the difference
a . sin(π/2) + 7 = 13
Subtract 7 from both sides
a . sin(π/2) = 6
Evaluate sin(π/2)
a . 1 = 6
Divide both sides by 1
a = 6
Hence, the value of a is 6 and the value of b is 7
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