We are to calculate for which of the situation will result in 3/4
A.
[tex]\frac{0.5ft}{6}=0.08333ft[/tex]B.
[tex]\begin{gathered} 1gal=128ounces \\ 0.25gal=x \\ x=128\cdot0.25=32ounces \\ 32ounces\text{ - }12ounces=20ounces \\ \frac{20ounces}{20}=1ounce\text{/bucket} \\ \end{gathered}[/tex]C.
[tex]\begin{gathered} A(lawn)=4800ft^2 \\ A(mowed)=1200ft^2 \\ \frac{A(mowed)}{A(lawn)}=\frac{1200}{4800}=\frac{1}{4} \\ A(left\text{ to be }mowed)=1-\frac{1}{4}=\frac{3}{4} \end{gathered}[/tex]Option C is the situation that produces the desired result