Respuesta :

Given:

The sequence is,

[tex]9,1,-7,-15,\ldots\ldots\text{....}[/tex]

The common difference is -8.

The recursive formula is expressed as,

[tex]\begin{gathered} a_n=a_{n-1}+d,\text{ for n}\ge2 \\ d=-8 \end{gathered}[/tex]

It gives,

[tex]\begin{gathered} a_1=9 \\ a_2=a_1-8=9-8=1 \\ a_3=a_2-8=1-8=-7 \\ a_4=a_4-8=-7-8=-15 \\ \Rightarrow a_n=a_{n-1}-8,\text{ for n}\ge2 \\ a_1=9 \end{gathered}[/tex]

Answer:

[tex]\begin{gathered} a_n=a_{n-1}-8,\text{ for n}\ge2 \\ a_1=9 \end{gathered}[/tex]

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