Given:
The sequence is,
[tex]9,1,-7,-15,\ldots\ldots\text{....}[/tex]The common difference is -8.
The recursive formula is expressed as,
[tex]\begin{gathered} a_n=a_{n-1}+d,\text{ for n}\ge2 \\ d=-8 \end{gathered}[/tex]It gives,
[tex]\begin{gathered} a_1=9 \\ a_2=a_1-8=9-8=1 \\ a_3=a_2-8=1-8=-7 \\ a_4=a_4-8=-7-8=-15 \\ \Rightarrow a_n=a_{n-1}-8,\text{ for n}\ge2 \\ a_1=9 \end{gathered}[/tex]Answer:
[tex]\begin{gathered} a_n=a_{n-1}-8,\text{ for n}\ge2 \\ a_1=9 \end{gathered}[/tex]