Question

A quadrilateral is inscribed in the circle.What is the value of x?20(6y + 12)(4x + 80°1688(6x-28)(5y + 3)18

Answer 1

4x + 8 + 6y + 12 + 5y + 3 + 6x - 28 = 360

10x + 11y + -5 = 360

10x + 11y = 365

Substituting the possible solutions

10(20) + 11y = 365

200 + 11y = 365

11y = 365 - 200

11y = 165

y = 165/11

y = 15

So, after doing this procedure for all the possible solutions, the only with a whole number as a result is the number 20.

So, the result is 20.