We start by obtaining the value of x in the model question
3x - 12 = 24
3x = 24 + 12
3x = 36
[tex]x\text{ = }\frac{36}{3}\text{ = 12}[/tex]We consider "Option A"
15x - 60 = 120
15x = 120 + 60
15x = 180
[tex]x\text{ = }\frac{180}{15}\text{ = 12}[/tex]Thus, Option A has the same solution as our model equation
Next, we consider "Option B"
3x = 12
[tex]x\text{ = }\frac{12}{3}\text{ = 4}[/tex]Option B does not have the solution as our model equation
Next, we consider "Option C"
[tex]\begin{gathered} 3x\text{ = 36} \\ x\text{ = }\frac{36}{3}\text{ = 12} \end{gathered}[/tex]This has the same solution as our model equation
Next, we consider "Option D"
x - 4 = 8
x = 8+ 4
x = 12
Option D has the same solution as our model equation
Lastly, we consider "Option E"
12x - 12 = 24
12x = 24 + 12
12x = 36
[tex]x\text{ = }\frac{36}{12}\text{ = 3}[/tex]Option E does not have the solution as our model equation