Respuesta :

We start by obtaining the value of x in the model question

3x - 12 = 24

3x = 24 + 12

3x = 36

[tex]x\text{ = }\frac{36}{3}\text{ = 12}[/tex]

We consider "Option A"

15x - 60 = 120

15x = 120 + 60

15x = 180

[tex]x\text{ = }\frac{180}{15}\text{ = 12}[/tex]

Thus, Option A has the same solution as our model equation

Next, we consider "Option B"

3x = 12

[tex]x\text{ = }\frac{12}{3}\text{ = 4}[/tex]

Option B does not have the solution as our model equation

Next, we consider "Option C"

[tex]\begin{gathered} 3x\text{ = 36} \\ x\text{ = }\frac{36}{3}\text{ = 12} \end{gathered}[/tex]

This has the same solution as our model equation

Next, we consider "Option D"

x - 4 = 8

x = 8+ 4

x = 12

Option D has the same solution as our model equation

Lastly, we consider "Option E"

12x - 12 = 24

12x = 24 + 12

12x = 36

[tex]x\text{ = }\frac{36}{12}\text{ = 3}[/tex]

Option E does not have the solution as our model equation

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