Question

1)The rotor on a helicopter turns at an angular velocity of 3.2x102 revolutions per minute. Express this angular velocity in radians per second.

Answer 1

The angular velocity in radians per second can be calculated as,

$\begin{gathered} \omega=(3.2\times10^2\text{ rev/min)(}\frac{2(3.14)\text{ rad}}{1\text{ rev}})(\frac{1\text{ min}}{60\text{ s}}) \\ =33.5\text{ rad/s} \end{gathered}$

Thus, the angular velocity of the rotor is 33.5 rad/s.