First let's calculate the slope of the curve
A = (8,0)
B = (11,4)
[tex]\begin{gathered} m=\frac{y2-y1}{x2-x1} \\ m=\frac{4-0}{11-8} \\ m=\frac{4}{3} \\ \end{gathered}[/tex]A straight line parallel to that curve has the same slope
First of all, remember what the equation of a line is:
y = mx+b
Where:
m is the slope, and
b is the y-intercept
m = 4/3
Now, what about b, the y-intercept?
[tex]\begin{gathered} b=y-mx \\ b=5-\frac{4}{3}\cdot4 \\ b=5-\frac{16}{3}_{} \\ b=-\frac{1}{3} \end{gathered}[/tex]The equation of the line that passes through the point (4,5) with a slope of 4/3
[tex]y=\frac{4}{3}x-\frac{1}{3}_{}[/tex]Blue line is the new bike path
Red line is the railroad