1) We have to solve for x.
We have a right triangle, so we can apply the Pythagorean theorem to relate the side lengths.
As x is the hypotenuse, we can write:
[tex]\begin{gathered} x^2=9^2+15^2 \\ x^2=81+225 \\ x^2=306 \\ x=\sqrt{306} \\ x\approx17.5 \end{gathered}[/tex]
Answer: x = 17.5
