Question

Diagonals FB and BD are drawn in regular hexagon ABCDEF. What is the ratio of the area of quadrilateral BDEF to the sum of the areas of triangles ABF and BCD?

Answer 1

In the regular hexagon labelled ABCDEF, all sides are of the sams measurement, that is;

$AB=BC=CD=DE=EF=FA$

With the diagonals Fb and BD, you now have two triangles formed which are, ABF and BCD. The area of each triangle is given as;

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