Question

The perimeter of a rectangle is 78 feet. The length of the rectangle is twice the width. Find the length and width of the rectangle.

Answer 1

Given:

Perimeter of rectangle is 78 feet

Let the width of the rectangle be w

Then the length of the rectangle be 2w

Now, the perimeter is given by the formula:

$P=2(l+b)$

Substitute l= 2w and b=w

$\begin{gathered} P=2(2w+w) \\ =2(3w) \\ =6w \end{gathered}$

Given perimeter = 78 feet so,

$\begin{gathered} P=6w \\ 78=6w \\ w=\frac{78}{6} \\ w=13 \end{gathered}$

Hence, the width of rectangle is 13 feet

The length of rectangle is 2w= 2(13)=26 feet.