2) Find the equation of the line passing through the points (1, -2) and (2, 4). Write the equatior slope-intercept form. OY=2x-4 y = -22 y= 6x - 8 y = -6x + 4 Si Premious Next docx

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The slope of a line that passes through points (x1, y1) and (x2, y2) is:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Replacing with the points (1, -2) and (2, 4),

[tex]m=\frac{4-(-2)}{2-1}=\frac{6}{1}=6[/tex]

The slope-intercept form of a line is:

y = mx + b

where m is the slope and b is the t-intercept

Replacing with point (1, -2) and m = 6:

-2 = 6(1) + b

-2 = 6 + b

-2 - 6 = b

-8 = b

Then, the equation is:

y = 6x - 8

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