Question

How much time would a force of 646 N need to stop a 82 kg object moving at 41 m/s (1 decimal place and no spaces between answer and units).

Answer 1

Answer:

The time is 5.21 s.

Explanation:

Given that,

Force F = 646 N

Mass m = 82 kg

Velocity v = 41 m/s

We need to calculate the acceleration

Using formula of force

F= ma

$a = \dfrac{F}{m}$

$a = \dfrac{646}{82}$

$a =7.87\ m/s^2$

We need to calculate the time

Now, using equation of motion

$v = u+at$

$41=0+7.87 t$

$t = \dfrac{41}{7.87}$

$t = 5.21\ s$

Hence, The time is 5.21 s.