ABC is dilated to form AA''C'Which proportion can be used to determine the length of BC ?

Triangle ABC is dilated from A'B'C so we can get the proportion from These two triangles are
[tex]\frac{AC}{A^{\prime}C^{\prime}}=\frac{BC}{B^{\prime}C^{\prime}}\Rightarrow\frac{4}{6}=\frac{BC}{8}[/tex]Hence The correct anser is the first one which is
[tex]\frac{4}{6}=\frac{BC}{8}[/tex]