We have the following:
the area of the triangle is given by the base and by the height of the triangle, in this case we are going to suppose that a square is a unit. therefore:
[tex]\begin{gathered} A_A=\frac{4\cdot5}{2}=\frac{20}{2}=10 \\ A_B=\frac{4\cdot5}{2}=\frac{20}{2}=10 \\ A_C=\frac{4\cdot5}{2}=\frac{20}{2}=10 \end{gathered}[/tex]
Which means that in reality the 3 triangles have the same area, although they are different, they present the same area
