Question

In the logistic population growth model, the per capita rate of population increase approaches zero as the population size (N) approaches the carrying capacity (K), as shown in the table. Assume that rmax = 1.0 and K = 1,500. You can then calculate the population growth rate for four cases where population size (N) is greater than carrying capacity. To do this, use the equation for population growth rate in the table.

Which population size has the highest growth rate?

a) N = 1,510
b) N = 1,600
c) N = 1,750
d) N = 2,000

Answer 1

The correct answer between all the choices given is the first choice or letter A, which is "N = 1,510". I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

Answer 2

According to the logistic equation, it is found that the population size that has the highest growth rate is:

a) N = 1,510

The growth rate of the logistic equation is given by:

$r = r_{MAX}N\frac{(K - N)}{K}$

For this problem, the parameters are:

• Maximum growth rate of $r_MAX = 1$.
• Carrying capacity of $K = 1500$.

Then, the growth rate for N = 1510 is:

$r = 1510\frac{(1500 - 1510)}{1500}$

$r = -10.07$

The growth rate for N = 1600 is:

$r = 1600\frac{(1500 - 1600)}{1500}$

$r = -106.67$

The growth rate for N = 1750 is:

$r = 1750\frac{(1500 - 1750)}{1500}$

$r = -291.67$

The growth rate for N = 2000 is:

$r = 2000\frac{(1500 - 2000)}{1500}$

$r = -666.67$

Thus, option a is correct, due to the higher value of r.

A similar problem is given at https://brainly.com/question/13229117