In the triangle below, if < C = 6x + 11, and < A = 3x + 20, find x.

Answer:
[tex]D\text{: 3}[/tex]Explanation:
Here, we want to get the value of x
From the diagram shown, what we have is an isosceles triangle
In an isosceles triangle, the base angles are equal
Thus:
Mathematically:
[tex]m\angle C\text{ = m}\angle A[/tex]We proceed to equate the values:
[tex]\begin{gathered} 6x+11\text{ = 3x+ 20} \\ 6x-3x\text{ = 20-11} \\ 3x\text{ = 9} \\ x\text{ = }\frac{9}{3} \\ x\text{ = 3} \end{gathered}[/tex]