We have the following:
[tex]\begin{gathered} 7x-2y=16 \\ 11x+6y=32.3 \end{gathered}[/tex]solving:
[tex]\begin{gathered} 7x=16+2y\rightarrow x=\frac{16+2y}{7} \\ \text{ replacing} \\ 11\cdot(\frac{16+2y}{7})+6y=32.3 \\ \frac{176}{7}+\frac{22}{7}y+6y=32.3 \\ 9.14y=7.16 \\ y=\frac{7.16}{9.14} \\ y=0.78 \end{gathered}[/tex]now, for x:
[tex]\begin{gathered} x=\frac{16+2\cdot0.78}{7} \\ x=\frac{16+1.56}{7}=\frac{17.56}{7} \\ x=2.5 \end{gathered}[/tex]Therefore, the answer is x = 2.5 and y = 0.78
