Question

Three bacteria are placed in a petri dish. The population will triple every day. The formula for the number of bacteria in the dish on day t is N(+) = 3(3), where t is the number of days after the three bacteria are placed in the dish. How many bacteria are in the dish seven days after the three bacteria are placed in the dish?

Answer 1

Answer:

6561 bacteria

Explanations:

The formula for the number of bacteria in the dish on day t is given as:

$N(t)=3(3^t)$

Seven days after the three bacteria are placed in the dish, t = 7

Substitute t = 7 into the given formula, N(t)

$\begin{gathered} N(7)=3(3^7) \\ N(7)\text{ = 3(}2187) \\ N(7)\text{ = }6561 \end{gathered}$

There are 6561 bacteria in the dish after 7 days