Question

consider the graph of f(x) = 5^x +1. Explain how to find the average rate of change between x=0 and x=4 what is the average rate of change?

Answer 1

SOLUTION

$\begin{gathered} \text{Average rate of change = }\frac{f\mleft(4\mright)-f\mleft(0\mright)}{4-0}_{} \\ \\ Si\text{nce x = 0 and x = 4} \\ f(x)=5^x+1 \\ f(4)=5^4+1 \\ f(4)=625+1=626 \\ f(0)=5^0+1 \\ f(0)=1+1=2 \\ \\ \text{Average rate of change = }\frac{f(4)-f(0)}{4-0} \\ \\ \text{Average rate of change = }\frac{626-2}{4-0} \\ \\ \text{Average rate of change = }\frac{624}{4} \\ \\ \text{Average rate of change = }156 \end{gathered}$