Okay, here we have this:
We are going to solve the provided equation, so we obtain the following:
[tex]\begin{gathered} 16^x\: =\: \mleft(1/4\mright)\: ^{x-5} \\ (4^2)^x=(4^{-1})^{x-5} \\ 4^{2x}=4^{-(x-5)} \\ 2x=-(x-5) \\ 2x=-x+5 \\ 2x+x=5 \\ 3x=5 \\ x=\frac{5}{3} \end{gathered}[/tex]
