Question

The area of a painting is 10x^2 + 26x + 12 ft squared the length is 5x + 3 ft what is the width of the painting?

Answer 1

The area of the painting is

$10x^2+26x+12=l\cdot w$

Where, l is length, and w is the width. Then, we have:

$10x^2+26x+12=(5x+3_{})\cdot w$$w=\frac{10x^2+26x+12}{5x+3}$

And we need to divide two polynomials:

Then, the width of the painting is 2x+4