The equation of a line is given as:
[tex]y-y_1=m(x-x_1)[/tex]where m is the slope and (x1,y1) is a point through the line. The slope is given as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]In this case we have the points (since 1986) (2,50200) and (14,63400), then the slope is:
[tex]\begin{gathered} m=\frac{63400-50200}{14-2} \\ m=\frac{13200}{12} \\ m=1100 \end{gathered}[/tex]Plugging the values we have the equation:
[tex]\begin{gathered} y-50200=1100(x-2) \\ y-50200=1100x-2200 \\ y=1100x+50200-2200 \\ y=1100x+48000 \end{gathered}[/tex]Therefore the equation we are looking for is:
[tex]y=1100x+48000[/tex]