we have
[tex]2^4+(\frac{1}{2})^3[/tex]simplifying
[tex]16+(\frac{1^3}{2^3})[/tex][tex]16+(\frac{1}{8})[/tex][tex]16\ast\frac{8}{8}+\frac{1}{8}[/tex][tex]\frac{16\ast8+1}{8}=\frac{128+1}{8}=\frac{129}{8}[/tex][tex]\frac{129}{8}=16.125[/tex][tex]\frac{1}{8}=0.125[/tex]and
[tex]16\frac{1}{8}=\frac{16}{8}=2[/tex]in conclusion
[tex]16+\frac{1}{8}\ne16\frac{1}{8}[/tex]however
since how the problem is written this is just syntaxis and this is open to a teacher interpretation so technically the values are not the same but can be represented the same way
