Given data:
The first coordinate is (-3, 5).
The second coordinate is (3, 3).
The equation of the line passing through the given points is,
[tex]\begin{gathered} y-5=\frac{3-5}{3-(-3)}(x-(-3)) \\ y-5=\frac{-2}{6}(x+3) \\ y-5=-\frac{1}{3}(x+3) \\ y=-\frac{1}{3}x+4 \end{gathered}[/tex]Thus, the equation of the line in slope-intercept form is y= -1/3 x+4.