Step 1;
[tex]\text{Probability of any event = }\frac{n\text{umber or required outcome}}{n\text{umber of sample space}}[/tex]Step 2:
[tex]\text{Probability = number of required event/number of sample space.}[/tex][tex]\begin{gathered} \text{Probability of defective = }\frac{4}{10}\text{ = 0}.4 \\ \text{Probability of not defective = }\frac{6}{10}\text{ = 0.6} \end{gathered}[/tex]Final answer
Therefore, the probability that the sample will not contain a defective computer
[tex]=\text{ }\frac{^4C_0\times^6C_4^{}}{^{10}C4}[/tex][tex]\begin{gathered} =\text{ }\frac{1\text{ }\times\text{ 15}}{210} \\ =\text{ }\frac{1}{14} \end{gathered}[/tex]