Question

You are ordering a hamburger and can get up to 6 toppings, but each topping can only be used once. You tell the cashier to surprise you with the toppings you get.What is the probability that you get 3 toppings? Express your answer as a fraction or a decimal number rounded to four decimal places.

Answer 1

Answer:

1/120

Explanation:

The number of possible toppings = 6

Each topping can only be used once.

We want to find the probability that you get 3 toppings.

$\begin{gathered} \text{P\lparen1st topping\rparen}=\frac{1}{6} \\ \text{P\lparen2nd topping\rparen}=\frac{1}{5} \\ \text{ P\lparen3rd topping\rparen}=\frac{1}{4} \end{gathered}$

Therefore, the probability that you get 3 toppings is:

$\begin{gathered} \text{ P\lparen3 toppings\rparen}=\frac{1}{6}\times\frac{1}{5}\times\frac{1}{4} \\ =\frac{1}{120} \end{gathered}$

The probability that you get 3 toppings is 1/120.