Respuesta :

Answer

(a) 1/6

(b) 2/3

Explanation

In a single roll of a die, the sample space is {1, 2, 3, 4, 5, 6}

(a) The odds in favour of rolling a ''five''.

The possible outcome of five is 1.

Therefore, the odds in favour of rolling a ''five'' will be:

[tex]P(rolling\text{ }a\text{ }five\rbrace=\frac{1}{6}[/tex]

(b) The Odds Against rolling a multiple of "three".

Multiple of three is {3, 6).

[tex]P(multiple\text{ }of\text{ }three)=\frac{2}{6}=\frac{1}{3}[/tex]

Hence, the odds against rolling a multiple of three will be:

[tex]1-\frac{1}{3}=\frac{2}{3}[/tex]

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