Find the current in a 5 Ω resistor connected to a battery with an internal resistance of 3 Ω if the emf of the battery is 9 V.Group of answer choices4.85 A3.00 A1.13 A1.80 A

Respuesta :

The correct answer is option C, 1.13 A.

Given,

The resistance of the resistor, R=5 Ω

The internal resistance of the battery, r=3 Ω

The emf of the battery, E=9 V

The current through the battery is given by Ohm's law. According to whch,

[tex]I=\frac{E}{R+r}[/tex]

Where I is the current through the resistor R.

On substituting the know values,

[tex]\begin{gathered} I=\frac{9}{5+3} \\ =1.13\text{ A} \end{gathered}[/tex]

Therefore the current in the 5 Ω resistor is 1.13 A

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