Question

A man pushes a lawn mower on a level lawn with a force of 199 N. If 38% of the force is directed horizontally, how much work is done by the man in pushing the mower 6.1 m? answer in:____J

Answer 1

Given:

The applied force on the lawn mower is,

$F=199\text{ N}$

38% of the force is directed horizontally.

The displacement of the lawn-mower is

$d=6.1\text{ m}$

To find:

The work done by the man

Explanation:

The horizontal force on the lawn mower is,

$\begin{gathered} F_H=F\times38\text{ \%} \\ =199\times\frac{38}{100} \\ =75.6\text{ N} \end{gathered}$

The work is,

$\begin{gathered} W=F_H\times d \\ =75.6\times6.1 \\ =461.2\text{ J} \end{gathered}$

Hence, the work is 461.2 J.