Question

Please help me with this quickly I have till 11:59pm but I still have a lot of questions. Please make it simple and easy.

Answer 1

Given the following expression:

$\frac{6x^2-7x-5}{3-x}$

We will simplify the expression as follows:

First, we will factor the numerator

$=\frac{(2x+1)(3x-5)}{3-x}$

As shown there is no common factors between the numerator and the denominator

so, the answer will be:

$\frac{(2x+1)(3x-5)}{3-x}$