Data
• The data is normally distributed.
,• Average: 53
,• Standard deviation: 4
,• Random individual: between 50 and 55.
Procedure
As it is normally distributed, we have to use Z:
[tex]Z=\frac{x-\mu}{\sigma}[/tex]Replacing our values for 50 and 55:
• 50
[tex]Z=\frac{50-53}{4}=-0.75[/tex]• 55
[tex]Z=\frac{55-53}{4}=0.5[/tex]Therefore, our probability is equal in terms of Z:
[tex]P(50To find the probability, we have to subtract as follows:[tex]P(-0.75-0.75)[/tex]Using the Standard Normal Table we can see that:
[tex]P(Z<0.50)=0.6915[/tex]While the other value we need:
[tex]P(Z>-0.75)=0.2266[/tex]Finally:
[tex]P(-0.75Answer: b.