Question

consider the function f(x)=-3(x+10)^2 what is the vertex of this function

Answer 1

Function given:

$f(x)=-3\cdot(x+10)^2$

The standard form of the parabola is:

$f(x)=a(x-h)^2+k$

where the vertex is ( h, k ).

Thus, the vertex is...

Answer:

$(-10,0)$