Answer:
c=5
Explanation:
Given the equation:
[tex]2c+5\left(c−5\right)=10[/tex]First, open the bracket:
[tex]\begin{gathered} 2c+5\left(c)−5(5\right)=10 \\ 2c+5c-25=10 \\ 7c-25=10 \end{gathered}[/tex]Next, add 25 to both sides:
[tex]\begin{gathered} 7c-25+25=10+25 \\ 7c=35 \end{gathered}[/tex]Finally, divide both sides by 7:
[tex]\begin{gathered} \frac{7c}{7}=\frac{35}{7} \\ c=\frac{5\times7}{7} \\ c=5\times\frac{7}{7} \\ c=5\times1 \\ c=5 \end{gathered}[/tex]The value of c in the equation is 5.
