Let x equals negative 31 times pi over 6 periodDetermine the reference angle of x

Given :
[tex]x=-\frac{31\pi}{6}[/tex][tex]\text{Substitute }\pi=180^o,\text{ we get }[/tex][tex]x=-\frac{31\times180^o}{6}[/tex][tex]x=-31\times30^o[/tex][tex]x=-930^o[/tex][tex]x=-930^o=-720-210[/tex][tex]x=-930^o=-2\times360-180-30[/tex]After two full rotating, and 180 degrees, the angle is 30 degrees in 3 rd quadrant.
The reference angle is the angle that the given angle makes with the x-axis.
Hence the required reference angle is 30 degrees.