Question

A 6-sided die is loaded in such a way where odd outcomes occur 2/9 of the time, and even outcomes happen the other 1/9 of the time. What is this die's expected value? 04.333 OB.4 OC. 35 OD. 3.25 Reset Selection

Answer 1

The odd outcome (1, 3 and 5) probability is 2/9, and the even outcome (2, 4 and 6) probability is 1/9. The expected value is given by:

$\begin{gathered} \sum_i^6i\cdot P(i)=(1+3+5)\cdot\frac{2}{9}+(2+4+6)\frac{1}{9}=2+\frac{12}{9}=3.33... \\ \end{gathered}$

Answer: Option A