Question

this is a graded assignment in which i got this answer wrong and would like to know how to properly compete it. please help and show work!

Answer 1

Given:

$\log _82$$\text{Let }\log _82=x$$2=8^x$$2=(2^3)^x$$2=2^{3x}$$1=3x$$x=\frac{1}{3}$$\log _82=\frac{1}{3}$