Question

To achieve an octet of valence electrons, an iodine atom will become an ion with what charge?

Answer 1

The octet rule can be satisfied when there are 8 electrons in the valence shell. In other words, to be stable, it must follow that of the electronic configuration of the noble gases. Iodine has an atomic number of 53, while its nearest noble gas is Xenon (54). Thus, it needs one more electron to achieve octet rule. So, Iodine is usually present as I-1 in ionic form.

Answer 2

Answer:  Anion with negative charge

Explanation: Iodine atom belongs to the Group 17 elements which are also known as Halogens.

The electronic configuration of the Iodine(I) =  [Kr] 4d10 5s2 5p5

Thus when it will gain one electron in order to complete its valence shell of electrons with 8 electrons, it will acquire a negative charge.

Thus it will become an anion, which is not so much ready to lose its electron.

                                          I(s) + e → I -(aq)