The acceleration = 2.77 m/s²
The distance = 112.185 m
Explanation:The mass of the toy car, m = 4 kg
The force, F = 15 N
Coefficient of Friction, µ = 0.1
The acceleration, a = ?
The frictional force is calculated as:
[tex]\begin{gathered} F_r=\mu mg \\ F_r=0.1(4)(9.8) \\ F_r=3.92N \end{gathered}[/tex]We can calculate the acceleration using the equivalent force formula:
[tex]\begin{gathered} \sum F=F-F_r \\ ma=15-3.92 \\ 4a=11.08 \\ a=\frac{11.08}{4} \\ a=2.77m/s^2 \end{gathered}[/tex]The acceleration = 2.77 m/s²
To get the distance covered, use the formula below:
[tex]\begin{gathered} S=ut+\frac{1}{2}at^2 \\ S=0(9)+0.5(2.77)(9^2) \\ S=112.185m \end{gathered}[/tex]The distance = 112.185 m
