The points given are:
(4, 1) and (10, 6)
We can find the slope using the formula below:
[tex]\text{slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]From the points given;
x₁=4 y₁=1 x₂ =10 y₂=6
substitute the values into the formula
[tex]\text{slope}=\frac{6-1}{10-4}[/tex][tex]=\frac{5}{6}[/tex]To find whether the line rises or falls or is horizontal, let's find the equation of the line
substitute x₁=4 y₁=1 and m=5/6 into y=mx + b and find the intercept(b)
1=5/6 (4) + b
1= 10/3 + b
1-10/3 = b
-7/3 = b
substitute m=5/6 and b=-7/3 into y=mx + b, this gives the equation of the line.
That is;
[tex]y=\frac{5}{6}x-\frac{7}{3}[/tex]From, this, since the slope is positive, then the line rises