Question

Please draw/show the phase change graph!!! I know the energy just need to figure out how to do the graph!!

Answer 1

Given:

Initial temperature of ice,

$T_i=-25^{\circ}C$

Mass of ice,

$\begin{gathered} m=15\text{ g} \\ =0.015\text{ kg} \end{gathered}$

Final temperature,

$T_F=55^{\circ}C$

The heat absorbed to bring the temperature of ice to 0°C is given as,

$Q_1=mC_i(0^{\circ}C-T_i)^{}$

Here, C_i is the specific heat of ice.

Substituting all known values,

$\begin{gathered} Q_1=0.015\times2093\times(0^{\circ}C-(-25^{\circ}C)) \\ =784.875\text{ J} \end{gathered}$

The heat absorbed to melt ice is given as,

$Q_2=mL$

Here, L is latent heat of fusion of ice.

Substituting all known values,

$\begin{gathered} Q_2=0.015\times33600 \\ =504\text{ J} \end{gathered}$

The heat absorbed by water to raise its temperature to 55°C is given as,

$Q_3=mC_w(T_F-0^{\circ}C)$

Here, C_w is the specific heat of water.

Substituting all known values,

$\begin{gathered} Q_3=0.015\times4200\times(55^{\circ}C-0^{\circ}C) \\ =3465\text{ J} \end{gathered}$

Therefore, the heat absorbed the ice to raise the temperature for -25° C to 55°C is ,

$Q=Q_1+Q_2+Q_3$

Substituting all known values,

$\begin{gathered} Q=784.875+504+3465 \\ =4753.875\text{ J} \end{gathered}$

Therefore, the the heat absorbed the ice to raise the temperature for -25° C to 55°C is 4753.875 J.

Phase change diagram: