Question

solve (8u^2+3u-4)+8u^2+3u-1)-(3u^2-3u-8)

Answer 1

The given expression is

$(8u^2+3u-4)+(8u^2+3u-1)-(3u^2-3u-8)$

First, we use the distributive property

$8u^2+3u-4+8u^2+3u-1-3u^2+3u+8$

Second, we reduce like terms

$\begin{gathered} 8u^2+8u^2-3u^2+3u+3u+3u-4-1+8 \\ 13u^2+9u+3 \end{gathered}$

Hence, the final expression is

$13u^2+9u+3$