We need to use the point-to-point equation of the line after finding the point-slope form of the line:
We need to identify the corresponding coordinates:
x1 = 2
y1 = 3
x2 = 3
y2 = 6
Then, we have:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]Thus
[tex]y-3=\frac{6-3}{3-2}(x-2)\Rightarrow y-3=\frac{3}{1}(x-2)\Rightarrow y-3=3(x-2)[/tex]Then, the line in the point-slope form that passes through the given points (2, 3) and (3,6) is
[tex]y-3=3(x-2)[/tex]