A semicircular turn on a racetrack is 915 m long, and has a radius of 291 mWhat is the centripetal acceleration of a car that completes the turn at a constant speed in 15 s?

Respuesta :

The centripetal acceleration is given by the formula

[tex]a_c=\frac{v^2}{r}[/tex]

Here, r is the radius and is equal to 291 m

For finding the value of centripetal acceleration, first we need to find velcity v,

The formula for velocity is

[tex]v=\frac{dis\tan ce\text{ }}{\text{time}}[/tex]

Substituting the values,

[tex]v=\frac{915}{15}[/tex]

So the velocity is 61 m/s.

Now, the value of velocity will be substituted in the centripetal acceleration formula

[tex]a_c=\frac{(61)^2}{291}[/tex]

Hence the value of centripetal acceleration is 12.78 meter per second squared.

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