Question

A semicircular turn on a racetrack is 915 m long, and has a radius of 291 mWhat is the centripetal acceleration of a car that completes the turn at a constant speed in 15 s?

Answer 1

The centripetal acceleration is given by the formula

$a_c=\frac{v^2}{r}$

Here, r is the radius and is equal to 291 m

For finding the value of centripetal acceleration, first we need to find velcity v,

The formula for velocity is

$v=\frac{dis\tan ce\text{ }}{\text{time}}$

Substituting the values,

$v=\frac{915}{15}$

So the velocity is 61 m/s.

Now, the value of velocity will be substituted in the centripetal acceleration formula

$a_c=\frac{(61)^2}{291}$

Hence the value of centripetal acceleration is 12.78 meter per second squared.