It is neither an odd nor an even function
I'll assume that the relationship is:
[tex]y=4+x[/tex]
In function notation, we can write this as follows:
[tex]f(x)=4+x[/tex]
For any even function it is true that:
[tex]f(x)=f(-x)[/tex]
For any odd function it is true that;
[tex]f(-x)=-f(x)[/tex]
Applying these rules to our function:
RULE FOR EVEN FUNCTION:
[tex]f(x)=4+x \\ \\ f(-x)=4+(-x) \therefore f(-x)=4-x \\ \\ f(x)\neq f(-x)[/tex]
It is not an even function!
RULE FOR ODD FUNCTION:
[tex]f(x)=4+x \\ \\ -f(x)=-4-x \\ \\ f(-x)=4+(-x) \therefore f(-x)=4-x \\ \\ f(-x)\neq -f(x)[/tex]
It is not an odd function!
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So the conclusion is:
It is neither an odd nor an even function
Even function: https://brainly.com/question/11309886
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