The first function is,
[tex]y=-2x^2+x+3[/tex]
The absolute value of the coefficient of x^2 in the above function is |-2|=2.
The second function is,
[tex]f(x)=\frac{x}{3}^2-x-11[/tex]
The absolute value of the coefficient of x^2 in the above function is
1/3.
The graph of the parabola will be wider for the function in which the absolute value of the coefficient of x^2 is smaller.
Since the absolute value of the coefficient of x^2 is smaller in the second function than the first function, the graph of the second function will display the widest parabola.
So, the answer is
[tex]f(x)=\frac{x}{3}^2-x-11[/tex]
