Question

In the laboratory, a student is directed to prepare a 0.359 M solution of red #40 dye in a 250.0mL volumetric flask. The molecular mass of red #40 is 496.42 g/mol. How many grams of solid dye should the student weigh out to prepare the solution?

Answer 1

ANSWER

The mass of solid dye the student will use to prepare the solution is 178.15 grams

STEP-BY-STEP EXPLANATION:

What to find? The grams of the solid dye

Giving parameters

The mole of red #40 dye = 0.359 M

The molecular mass of red#40 = 496.42g/mol

The grams of the red#40 dye can be calculated by using the below formula

$\begin{gathered} \text{Mole = }\frac{\text{ reacting mass}}{\text{molar mass}} \\ \text{Introducing cross multiply} \\ \text{ reacting mass = mole x molar mass} \\ \text{ Reacting mass = 0.359 x 496.24} \\ \text{ reacting mass = 178.15 grams} \\ \end{gathered}$

Hence, the mass of solid dye the student will use to prepare the solution is 178.15 grams