Question

Bill took a test and got a 65%. the median was 59% and the standard deviation was 5.2. what was his z-score?

Answer 1

Answer:

1.15

Step-by-step explanation:

To find the z-score, you can use the formula:

$\text{Z-score} = \dfrac{\text{X} - \text{Mean}}{\text{Standard Deviation}}$

Where:

- X = Bill's score (65%)

- Mean = Median (59%)

- Standard Deviation = 5.2

$\text{Z-score} = \frac{65 - 59}{5.2} \\\\\text{Z-score} = \frac{6}{5.2} \\\\ \text{Z-score} \approx 1.15$